(y^2+3y-4)-(4y-6)=y^2+6

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Solution for (y^2+3y-4)-(4y-6)=y^2+6 equation:


Simplifying
(y2 + 3y + -4) + -1(4y + -6) = y2 + 6

Reorder the terms:
(-4 + 3y + y2) + -1(4y + -6) = y2 + 6

Remove parenthesis around (-4 + 3y + y2)
-4 + 3y + y2 + -1(4y + -6) = y2 + 6

Reorder the terms:
-4 + 3y + y2 + -1(-6 + 4y) = y2 + 6
-4 + 3y + y2 + (-6 * -1 + 4y * -1) = y2 + 6
-4 + 3y + y2 + (6 + -4y) = y2 + 6

Reorder the terms:
-4 + 6 + 3y + -4y + y2 = y2 + 6

Combine like terms: -4 + 6 = 2
2 + 3y + -4y + y2 = y2 + 6

Combine like terms: 3y + -4y = -1y
2 + -1y + y2 = y2 + 6

Reorder the terms:
2 + -1y + y2 = 6 + y2

Add '-1y2' to each side of the equation.
2 + -1y + y2 + -1y2 = 6 + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
2 + -1y + 0 = 6 + y2 + -1y2
2 + -1y = 6 + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
2 + -1y = 6 + 0
2 + -1y = 6

Solving
2 + -1y = 6

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1y = 6 + -2

Combine like terms: 2 + -2 = 0
0 + -1y = 6 + -2
-1y = 6 + -2

Combine like terms: 6 + -2 = 4
-1y = 4

Divide each side by '-1'.
y = -4

Simplifying
y = -4

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